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Water distribution math

The math on the distribution exam, with pressure and head at the center, plus the water audit, velocity, wells, and pumping.

June 2026
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The short answer

Distribution exam math centers on pressure and head: feet times 0.433 equals psi, and psi times 2.31 equals feet, so a tank 95 feet up puts about 41 psi on the main below. Other core math includes per-capita demand, water loss (produced minus billed, over produced), velocity (flow divided by area), well drawdown and specific capacity, storage turnover, friction loss, fire-flow sizing, and pump horsepower. Entry level covers conversions and pressure-to-head; Class III adds friction loss and fire flow; Class IV adds system curves and Ohm's law.

What you will be able to do

You can convert between pressure and head using the 0.433 and 2.31 factors. You can calculate per-capita demand and water loss percentage from production and billing data. You can find velocity in a main from flow and pipe area. You can work well drawdown, specific capacity, and pump horsepower problems. You can match each math topic to the exam class where it first appears.

The math on the water distribution exam

Distribution math leans on a handful of relationships you can carry in your head, with pressure and head at the center. This is the map. The formulas are on the water distribution formula sheet and the teaching is in operator math fundamentals.

What you work

Start with the shared core: convert flow and units, find a pipe or tank volume, and run a chlorine dose off the pounds formula. Then the distribution-specific math:

  • pressure and head, the relationship that runs the system: feet equals psi times 2.31, and psi equals feet times 0.433, so a tank 95 feet up puts about 41 psi on the main below it
  • per-capita demand, total daily use divided by population
  • water loss, produced minus billed over produced, the audit number that finds your leaks
  • velocity in a main, flow divided by area, with the area from 0.785 times the diameter squared
  • wells: drawdown and specific capacity
  • storage turnover and, higher up, friction loss and fire-flow sizing
  • pumping horsepower and the energy cost behind a booster or well pump

How it climbs by class

Entry wants the conversions, a volume, the pressure-to-head swap, and per-capita demand. Class II brings velocity, the water audit, wells, and pump horsepower. Class III is the hinge, with head and friction loss, fire-flow and storage sizing, and pump efficiency. Class IV adds system curves, electrical work with Ohm's law, and multi-step optimization.

A couple worked the exam's way

An elevated tank sits 95 feet above the main. The pressure it creates is 95 times 0.433, which is about 41 psi. Run it the other way and 50 psi is 50 divided by 0.433, or about 115 feet of elevation.

A utility produced 2.8 MGD and billed 2.1. Water loss is 2.8 minus 2.1, over 2.8, times 100, which is 25 percent. That is high, the kind of number that says go find the leaks.

Where points slip

The pressure-and-head conversion is easy to flip under time pressure, so anchor it: pressure is the smaller number, and you multiply by 2.31 to get the taller column of water. And keep MGD and gallons per minute straight in the audit and velocity math.

Study this

Keep the water distribution formula sheet close, work the free practice tool by hand, and confirm in the operator calculator. This track's exam page is water distribution, and your state's fees and dates are on your state's page.

Further reading
Looking for your state? Find your state for certification rules, renewal, and who to call, one page per state.
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